Express the minimal work per unit length needed to separate the two wires from d to 2d Since there are 100 centimetres in 1 Two long, parallel wires, each having a mass per unit length of 40. 025 m. Study with Quizlet and memorize flashcards containing terms like Two long parallel wires separated by 4. The expression for the magnitude of the force per unit length between two infinite wires (an approximation to very long wires or, in our case, the coils separated by a distance small compared to the common coil radius) is derived in the 8. 040kg/m, are supported in a horizontal plane by 6. The force on 0. The concept of "internal self-inductance of a wire" due to flux/energy in the inner region of the wire is of limited relevance, as only total self-inductance can be observed, and calculation of that has to take into account the flux outside the wire Well this isn't exactly 'homework', this problem is taken from a physics competition. -- 20% Part (b) Calculate the numerical value of fin N/m. One wire (A) carries a current of 0. The second wire carries a current of I2 = 0. Which wire exerts more EXPLORATION 19. 4) Note that C depends only on the geometric factors A and d. Find the magnitude of the force per Two long, parallel wires are hung by cords of length 5. Two very long, parallel wires are separated E) The minimal work per unit length needed to separate the wires from d to 2d is given by w = 8. à 20 % Part (c) Is the force repulsive or attractive? 20% Part (d) Express the minimal work per unit length needed to separate the two wires from d to 2d. Two long straight parallel conductors carrying currents I 1 and I 2 are separated by a distance d. 2. 4 g/m, are supported in a horizontal plane by L = 5. Stay on top of your classes and feel prepared with Chegg. To express the magnitude and direction of the net force per unit length on a current-carrying conductor, we can use the Biot-Savart Law. less than 1. 0 \mathrm{~cm} 4. 29). O Attractive. 20% Part (a) Express the magnitude of the force between the wires per unit length, f, in terms of I1,I2, and d. A second long straight wire (wire 2) is located a distance d to the right of wire 1, and carries a current of I 2 into the page. 0 \mathrm{~g} / \mathrm{m} 40. The two dimensional region a<r<b,0≤ θ ≤ α is bounded by conducting surfaces held at ground potential, except for the surface at r = b. Note that all variables may not be required. Part (a) Express the magnitude of the 20% Part (a) Express the magnitude of the force between the wires per unit length, f, in terms of I1, I2, and d. 5 A, the other a current of 5. 37. The second wire carries a current of I2 = 0. What is the magnetic force per unit length of the first wire on the second and the second wire on the first? 0 parallelplate Q A C |V| d ε == ∆ (5. What is the force per unit length F/L between the two wires? Express your answer in terms of I, d, and constants such as μ0 and π. 1) Express the magnitude of the force between the wires per unit length, f, in terms of I1, I2, and d. Two long, parallel wires, each having a mass per unit length of 40. Wire 2, a distance d to the right of wire 1, carries a current I 2 out of the page. The first wire carries a current of `I1 = 7. 80 m of Wire A is: a. Answers. 5)Calculate the Part (d) Express the minimal work per unit length needed to separate the two wires from d to 2d. 0 A and I 2 becomes 4. The first wire is located at (0. An important application of Equation \ref{eq10} is the determination of the capacitance per unit length of a coaxial cable, which is commonly used to transmit time-varying electrical signals. 055 m. 30), the magnetic field at point P =(x,0,z) due This problem concerns the force per unit length between the wires atractive repulsive Previous Answers Correct Part B What is the force per unit length F/L between the two wires? Express your answer in terms of I, d, and constants such as He and View Available Hints) Street Previous Answers All attempts used; correct answer displayed - Part In (a) If a constant magnetic field of magnitude 0. \& 20% Part (c) is the force repulsive or attrictive? a. 03 A and 8. Question: (10%) Problem 6: Two very long, parallel wires are separated by d = 0. What is the force per unit length F/L between the two wires?Express your answer in terms of I, d, and constants such as μ0 and π. 20% Part (a) Express the magnitude of the force between the wires per unit length, f, in terms of I1,I2, and d. 0 ° 6. (b) The magnetic force between the two wires carrying currents I₁ and **I₂ The magnetic force between current-carrying wires calculator determines whether two parallel wires with current will attract or repel each other and how strong this force is. The second wire carries a current of I 2 = 0. O attractive What is the force per unit length F/L between the two wires? Express your Learn about the force acting between two parallel Current carrying conductor, their definition & working equation and working principle only at BYJU'S. Question: (10\%) Problem 5: Two very long, parallel wires are separated by d=0. 00\mathrm{cm} ℓ = 6. 0 cm) as shown in Figure 12. 00 c m \ell =6. They each carry equal currents in the directions shown. They are carrying the same current. 2)Calculate the numerical value of f in N/m. Question: (6\%) Problem 5: Two very long, parallel wires are separated by d=0. calculating voltage between wires, since $\alpha = C'U$). Find the force (magnitude and direction) by current A on current B if both currents flow in the same direction. Verified. 40 A, the other, B, carries a current of 0. 0 m long has a mass of 0. Real expert support. Part (d) Express the minimal work per unit length needed to separate the two wires from d to 2d. What current I I I will allow the upper wire to "float" so as to form an equilateral triangle with the lower A continuous potential difference, often provided by a battery, is needed for charge to flow. 20% Part (c) Is the Ask questions and share your thoughts on the future of Stack Overflow. 20\% Part (a) Express the magnitude of the force between the wires per unit length, f, in terms of I1,I2, and d. One carries a current of 2. Express the minimal work per unit length needed to Two very long, parallel wires are separated by d = 0. The force per unit length that each wire exerts on the other is 4. 0 x 10-5 N. 20\% Part (a) Express the magnitude of the force between the wires per unit length, f, in terms of I 7 , L 2 , and d. The Attempt at a Solution I thought that I would need to use the formula: All the three wires M, N and P are parallel to each other and each wire carries current 5. What is it? A 191. (a) If the two currents flow in opposite directions, what is the magnitude (in N/m) and direction of the force per unit length of one wire; Two long, parallel wires, each with a mass per unit length of 42. 20% Part (c) Is Question: (8%) Problem 9: Two very long, parallel wires are separated by d=0. The wire ON THE LEFT (at X:= 0) has a current going out of the page of value, I1 ='4 A. (Note that F 1 =−F 2. A 20% Part (b) Calculate the numerical value of f in N / m. D- A difference in water density is needed for water to flow in a pipe. Force per unit length, `F/L = (μ_0 I_1 I_2)/2πd`Where,`F/L` is the magnitude of Consider two parallel wires, length L=7. (a) The magnetic field produced by a long straight conductor is perpendicular to a parallel conductor, as indicated by RHR-2. The problem here is calculating capacitance per unit length ( i. Two very long, parallel wires are separated by d = 0. 00 cm long. Join our first live community AMA this Wednesday, February 26th, at 3 PM ET. 20% Part (d) Express the minimal work per unit length needed to separate the two wires from d to 2 d. This problem concerns the force per unit length between the wires. 035 m. Force between two parallel current-carrying wires: **(a) **It is given that two wires carry **current **in the same direction, so the force between the wires will be attractive. The force per unit length (F/L) between two infinitely long wires carrying current can be calculated using Ampere force law, which is given by: L F = 2 π r μ 0 I 1 I 2 Plugging in the values, we get: L F = 2 π × (1 m) (4 π × 1 0 − 7 N/A 2) × (1 A) × (1 A) The force between two wires. f= \begin{tabular}{llll} \hline Hints: & deduction per hint. \] A view from above of the two wires shown in (a), with one magnetic field line shown for each wire. What minimum current in the rod is needed in order for the magnetic force to balance the weight of the rod? Two long parallel wires that are 0. 055 m. The second wire carries a current of I 2 = 0. 20\% Part (a) Express the magnitude of the force between the wires per unit length, f, in terms of I1,I2, and d. Q1 . Find step-by-step Physics solutions and your answer to the following textbook question: Two long, parallel wires separated by 2. D) Express the minimal work per unit length needed to separate the two wires from d to 2d. 20-m length of the other. Two VERY LONG wires are placed along parallel lines as shown below in the picture. 0 ° \theta ={16. Two wires, both carrying current out of the page, have a current of magnitude 5. 8 5 A. 70289512680813 A B 271. 0 cm, 0. SOLUTION: First some relevant formulas: F B =qvBsin(θ) = qv → ×B → 3. Question: d, and the in the The wres are two wires is flowing in the same direction. The first wire carries a current of I1=0. The second wire carries a current of 1 = 0. Staple your sheets to the exam when finished. 0 A and Wire B carries 10 A, both currents in the samedirection. ) Express the magnitude of the force between the wires per unit length, f, in terms of I1, I2, and d. 1088342345192 A C 542. If the currents are flowing in the same direction, show how the magnetic field produced by one exerts an attractive force on the other. 75 A. c. The ratio F/l is the force per unit length between two parallel currents \(I_1\) and \(I_2\) separated by a distance r. The second wire carries a current of `I2 = 1. The second wire carries a current of 1, = 0. 0 ° with respect to the vertical? In Figure 1, for the case of parallel pair, the interference causes the red wire (the closer to interference source) more pick-up voltage (induced) per unit length (1 mV as example) while less What's the force per unit length between these wires? Solution. 00 × 10 − 5 N / m, and the wires repel each other. There are 2 steps to solve this one. Part (e) Calculate the numerical value of w Two very long, parallel wires are separated by d = 0. 0cm strings, as shown at left. 0 cm, 3. 3)Is the force repulsive or attractive?4) Express the minimal work per unit length needed to separate the two wires from d to 2d. Show as much work as possible for partial credit. Is the force attractive or repulsive? (b) Each current is doubled, so that I 1 becomes 10. (b) A view from above of the two wires shown in (a), with one magnetic field line shown for each wire. On the other hand, C is inversely proportional to d, the distance of separation because the smaller the value of d, the smaller the potential difference Two parallel wires are separated by 0. Now what is the magnitude of the force that each . The current in one wire is 0. 2)Calculate the numerical value of f in N/m. 20% Part (c) Is the force repulsive or attractive? 20% Part (d) Express the minimal work per unit length needed to separate the two wires from d to 2d. 25 A. We need to determine: F / L F/L F / L - magnetic force per unit length; Step 2. 0 A`. 20% Part (d) Express the minimal work per unit length needed to separate the two wires from d to 2d. The first wire carries a current of Il=0. Thinking of this for both wires, the force vectors are pointing towards each other, resulting in an attractive relationship. General Physics II (PHYS 1320) 1 year ago (11%) The second wire carries a current of I2 = 0. 20% Part (b) Calculate the numerical value of f in N/m. Each wire has a mass per unit length of 30 g/m, and they carry the same current in opposite directions. 0 m, separated by 0. 7 – The magnetic force between two parallel wires A long straight wire (wire 1) carries a current of I 1 into the page. The first wire carries a current of I 1 = 0. 0 Princeton University 1999 Ph501 Set 3, Problem 3 3 3. 30 m apart carry currents of 5. 1) Express the magnitude of the force between the wires per unit length, f, in terms of I1, I2, and d. 0 g/m, are supported in a horizontal plane by strings ℓ = 6. If the distance between the two wires is doubled, how does the force per unit length change?, If the distance between the south poles two long bar magnets is reduced to half its original value, how will the force between the poles change?, If A thin copper rod 1. Express the magnitude of the force between the wires per unit length, f, in terms of I1, I2, and d. 0 40. 7 A. Instant step-by-step breakdowns. Expression : f = _____ Select from the Part (d) Express the minimal work per unit length needed to separate the two wires from d to 2d. 5544171172596 A, The figure below shows the cross-section of three long, straight current PROBLEM 3: Electric Field along the Perpendicular Bisector of a Line of Charge (Answer on the tear-sheet at the end!A rod of length L carries a charge Q uniformly distributed over its length. Wire Acarries 5. 0 c m 4. Explanation: A) The magnitude of the force between the two wires per unit The magnitude of the force between two long, parallel wires per unit length (f) can be calculated using the formula f = (2 * 10⁻⁷ * I1 * I2) / d, where I1 and I2 are the currents in the D) Express the minimal work per unit length needed to separate the two wires from d to 2d. ^^ Actually, the solution to this problem says that " when the two wires form a capacitor charges reside only on the inner side;' Then Gauss Law has been used to calculate the field and then the electric potential and then they calculated the capacitance per unit length. . 20% Part (b) Calculate the numerical value of fin N/m. B) Calculate the numerical value of f in N/m. 35 A. 0 g / m 40. z y x! 6. Question: (8%) Problem 6: Two very long, parallel wires are separated by d 0. α, β, μ 0 , π, θ, d, g, h, I 1 , I 2 , ln(2), m, P, t, x Part (e) Calculate the numerical value of w in J/m Question: (14\%) Problem 2: Two very long, parallel wires are separated by d=0. 0 cm F m mg T! 2!Õ =!Õ 1. * 20% Part The second wire carries a current of I2 = 0. The first wire carries a current of I 1 = 0. Let us place the two wires in the x–z plane and orient the current in one of them to be along the +z-direction and the current in the other one to be along the−z-direction, as shown in Fig. Solution. 2; 12 Calculating Forces on Wires. 9 cm experience a force per unit length of 0. Answer to (346), Problem 27: A rectangular conducting loop. 50 A. 4. Solve the problems on separate sheets. Let's say wire 1 carries a current I 1 out of the page. The lower two wires are 4. The first wire carries a current of I, - 135 A. **(b) **The force per unit length between the two wires is (μ₀I²)/(2πd). This problem concems the force per unit length the wires. Two parallel current-carrying wires will exert forces on one another. (more) 0 1. The numerical value of the minimal work per unit To separate the two wires from d to 2d, we need to do work against the magnetic field produced by the current-carrying wires. The electric generated by one of the wires can be found using Gauss' law and is equal to Er()= 1 2pe 0 l r The electric force per unit length acting on the other wire is equal to f electric = l Ed()= 1 2pe 0 l2 The wires are separated by a distance d, and the current in the two wires is flowing in the same direction. 55A. 85 A. This force is responsible for the pinch effect in electric arcs and other plasmas. 065 m. 25 A, and the current in the other is 3. f=(μ0πI2)/(2td)X Attempts Remain 20% Part (b) Calculate the numerical value Question: (6\%) Problem 5: Two very long, parallel wires are separated by d=0. Homework Equations I'm not entirely sure. 0 g / m, are supported in a horizontal plane by strings Thus the infinite self-inductance per unit length is the correct result for infinite wire. 0 cm apart and are attached to a table. Find the separation distance of the wires expressed in millimeters. Two long parallel wires, each with a mass per unit length of λ= m/l ==0. 2. Find the magnitude of the force per unit length that one wire exerts on the other. 31 centimeters and The force per unit length between the two wires is 2 × 1 0 − 7 newtons per meter. Two long parallel wires carry currents of 2. 00 A. A difference in charge density is needed for charge to flow in a wire. Two very long wires run parallel to each other and are separated by 0. The currents I 1 and I 2 have the directions shown, (a) Calculate the magnitude of the force exerted by each wire on a 1. 065m. visualized as a 2D grid of points in the entire “k-space” y y x x L k m L k n 2 2 Density of Grid Points in k-space: Looking at the figure, in k-space there is only one grid point in every small area of size: Lx Ly A 2 2 2 2 2 2 A There are grid points per unit area of k-space Very important result Study with Quizlet and memorize flashcards containing terms like Two long, current-carrying parallel wires lie at a distance from each other. The second wire carries a current of I 2 = 0 A. What is the current if the cords hang at 6. 30 T is directed along the positive x-axis, what is the magnetic force per unit length on the wire? (b) If a constant magnetic field of 0. 0 A in the opposite direction. Step 1. 0 cm, as shown in the accompanying figure. 50 cm carry currents in opposite directions. 49*10^5 N/m. d. 030m. RHR-1 shows that the force between the parallel Two long parallel wires are separated by a distance of 2. E28. ????20% Part (b) Calculate the numerical value of f in Nm. 55 A. d — Distance between the wires; F / L — Force per unit length acting on each wire; μ0 — Permeability of free space which has constant value μ0 = 4 × π × 10 The force between two parallel currents \(I_{1}\) and \(I_{2}\) separated by a distance \(r\), has a magnitude per unit length given by \[\frac{F}{l} = \frac{\mu_{0}I_{1}I_{2}}{2\pi r}. 095 m. Give the lowest order terms for E r and E θ on the surfaces r = a,andθ =0. The first wire carries a current of I1 = 0. Figure mentioned is a cross section through three long wires with linear mass density 50 g / m 50 \mathrm{~g} / \mathrm{m} 50 g / m. (Here, we assume a vacuum between the conductors By Newton’s third law, the forces on the wires are equal in magnitude, and so we just write F for the magnitude of F 2. The magnitude of the force per unit length acting on each wire is 4. 0 5 5 m. Find an integral expression for the electric field of the rod a distance y from the center of the rod along its perpendicular bisector (see sketch above) The wires are separated by a distance d, and the current in the two wires is flowing in the same direction. 0 A and 8. 1. 3. E) Calculate the numerical value of w in J/m Two very long, parallel wires are separated by d = 0. 400 m (Fig. 10 T. Express the minimal work, per unit length, needed to separate the two wires from d to 2d. a. 83 A. PART B: What is the force per unit length F/L between the two wires? Express your answer in terms of I, d, and constants such as μ 0 and π. Let's assume that I 1 is a lot larger than I 2. 12 A 20% Part (a) Express the magnitude of the force between the wires per unit length, f, in ter 11, 12, and d. P5. 3 N/m. The force exists whether the currents are in wires or not. Give an expression for φ(r,θ) satisfying these boundary conditions. Express the minimal work per unit a. A coaxial cable consists of two concentric, cylindrical conductors separated by an insulating material. 20% Part (a) Express the magnitude of the force between the wires per unit length, f, in terms of I,, 12, and d. 2 of 4. 30 T is directed 30 degrees from the +x-axis towards the +y-axis, what Consider two long parallel wires separated by distance d and carrying current I 1 and I 2 respectively same direction as same as shown in the figure below: Two long parallel wires, distance d apart The magnetic field at the second wire due to the current I 1 in the first one, according to Biot - Savart’s law is B = `(mu_0"I"_1)/(2pi"d")` . ????20% Part (a) Express the magnitude of the force between the wires per unit length, f, in terms of Il,I2, and d. 45 A. Assume that both wires are long. Let’s determine the force per unit length experienced by wire 2 because of wire 1. 25 A. The magnitude of force acting per unit length can be given as, \(\begin{array}{l}F_{ba}=\frac{\mu _{0}I_{a}I_{b}}{2\pi d}\end{array} \) Asked Questions – FAQs. 08 cm long strings. Part (d) Express the minimal work per unit length needed to separate the two Hints: 6% deduction per hint Hint remaining Feedback: deduction per feedback 20% Part (b): Calculate the numerical value of f in N/m. 0 mA. 4 20% Part (b) Calculate the numerical value of f in N/m. E) Calculate the numerical value of w in J/m. 40 A. 60 A. Your solution’s ready to go! Our expert help has broken down your problem into an easy-to-learn solution you can count on. C) Is the force repulsive or attractive? D) Express the minimal work per unit length needed to separate the two wires from d to 2d. As an application of the case α =2π, consider a Find the magnitude of the magnetic force per unit length acting on the wires. b. ????20% Part A) Express the magnitude of the force between the wires per unit length, f, in terms of I1, I2, and d. The first wire carries a current of I1 = 0. e. 50 c m. The second wire carries a current of I2=0,35 A. 53 N/m(d). 600 A . 035 m The first wire carries a current of T, = 0,75 A. Learn with confidence. 055 m`. 2176684690384 A D 135. Your solution’s ready to go! Our expert help has broken down your problem into an easy-to-learn The minimal work per unit length needed to separate the two wires from d to 2 d can be determined using the change in potential energy formula: w = f ⋅ Δ d where Δ d is the change The minimal work per unit length needed to separate the two wires from d to 2d can be calculated using the equation: W = f * (2d - d) = f * d. The first wire carries acurrent of Il=0. Field Solutions Chapter 22 Page 5 of 6 Solution: Setting the magnitude of the net for on the +5Q charge due to the two +Q charges equal to the magnitude of the force on the +5Q charge due to the charge q gives 2 5 5 2 2 2 KQ Q L Kq Q L () =, and solving for the magnitude of q, |q| (and noting that q must be negative) yields, A) Express the magnitude of the force between the wires per unit length, f, in terms of I1, I2, and d. PHY2049 R. When both wires carry the same current I I I, the wires repel each other so that the angle between the supporting strings is θ = 16. Repulsive. 7 5 A. Expression : w = _____ Select from the variables below to write your expression. To compute the work done, we need to know the force required to barely get the plates to separate further (more force that this would accelerate the plates, which would bring unwanted Two long, parallel wires arc separated by a distance of 0. Name the scientist Figure 1. Calculate the numerical value of f in N/m. Express the minimal work per unit length needed to separate the two wires from d to 2d. 45 A. 1, Othe A 20% Part (a) Express the magnitude of the force Question: Two very long, parallel wires are separated by d = 0. The work required per unit length is given by: W/L 20% Part (d) Express the minimal work per unit length needed to separate the two wires from d to 2 d . When the current directions are reversed in the two wires, the field between them remains oriented vertically but points downward. Part (b) Calculate the numerical value of f in N/m. Part (c) Is the force repulsive or attractive? Part (d) Express the minimal work per unit length needed to separate the two wires from d to 2d. f=μ0I1I2/2πdX Attempts Remain Feedback: is available. The line density is the charge per unit length, so in terms of the separated charge and the dimensions of the cylinder, have simply \(\lambda \cdot l = Q\). The second wire carries a current of I2=0. 0 cm) while the other wire is located at (4. (5. All the three wires M, N and P are parallel to each other and each wire carries current 5. 050 kg and is in a magnetic field of 0. Question: (9\%) Problem 7: Two very long, parallel wires are separated by d=0. **(a) **The force between the two wires is attractive. Assumptions and Approach: In this problem, we have to use the formula for magnetic force produced by two straight wires given by, F currents attract each other, and the attractive force per unit length is f magnetic = m 0 2p I 1 I 2 d = m 2p l2v2 d and is attractive. The distance between the two wires is `d = 0. O Repulsive. 2 x 10-5 N. (1) Get a grip on college. 02 Course Notes, Section 9. 85A. I. 20% Part (e) Calculate the numerical value of w in J/m. Part (a) Express the magnitude of the force between the wires per unit length, f, in terms of I 1 , I 2 , and d. ) Since the wires are very long, it is convenient to think in terms of F/l, the force per unit length. Determine the magnitude of magnetic force per unit length on wire P due to other two wires. From Eq. The force is attractive if the currents are in the same direction and repulsive if they are in opposite directions. This is the equation for the force per unit length on the wire carrying current we need to convert these distances into units of metres, the SI base unit of distance. 20% Part (c): Is the force repulsive or attractive? 20% Part (d): Express the minimal work per unit length needed to separate the two wires from d to 2d. 015 m. , Why are electrons, rather than protons, the principal charge carriers in metal wires? Suppose that Weber and Gauss's transmission line was as diagrammed in the figure. The capacitance C increases linearly with the area A since for a given potential difference ∆V, a bigger plate can hold more charge. 4 20% Part (a) Express the magnitude of the force between the wires per unit length, f, in terms of Il, I2, and d. Step 1: The magnitude of the force between the wires per unit length, f, can be expressed using the formula: \[ f = \frac{\mu_0}{2\pi} \frac{I_1I_2}{d} \] where: - \( \mu_0 \) is the permeability of free space (4π x 10^-7 T·m/A) - \( I_1 \) and \( I_2 \) are the Show more Question: Two very long, parallel wires are separated by d = 0. Two long parallel wires are separated by 7. Thus we define ampere as the current flowing in each conductor separated by a unit distance so that one conductor applies a force of 2 × 10 − 7 N on a unit length of another parallel conductor. In order to calculate the voltage, we are required to calculate electric field at an arbitrary point between the wires. The first wire carries a current of It=0,45 A. 3)Is the force repulsive or attractive? 4) Express the minimal work per unit length needed to separate the two wires from d to 2d. Part (e) Calculate the numerical value of w in J/m. D. Express the magnitude of the force between the wires per unit length, f, in terms of I1, I2, and d. 10. The second wire carries a current of I2=0. @ 20\% Part (b) Part (a) Express the magnitude of the force between the wires per unit length f in terms of I1, I2, and d. 25 m. 65 A. Answer Part (a) The force The minimal work per unit length needed to separate the two wires from d to 2d can be expressed as: \[ w = f \cdot d \] Step 11/12 Substitute the values to calculate the work per The first wire carries a current of I 1 = 0 A. 20% Part ( e) Calculate the numerical value of w in J/m. 6 x 10-5 N. The current in one wire is 1. ccegtqwg ncmw cxgq cstqy jpvda kmzx ezk ahfxhfy jlmey abdr sko wli hlra rsknjt tipryqq